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Waveguides and Resonant Cavities

Common waveguide geometries.

Common waveguide geometries.

Mode typeLongitudinal field condition
TEMEz=0E_z=0 and Hz=0H_z=0
TEEz=0E_z=0, Hz≠0H_z\ne0
TMHz=0H_z=0, Ez≠0E_z\ne0

Hollow single-conductor waveguides support TE and TM modes, not TEM modes.

A TEM field can be written in terms of an electrostatic potential over the guide cross-section:

Et=−∇tV,∇t2V=0.\mathbf E_t=-\nabla_tV, \qquad \nabla_t^2V=0.

The complete wall of a hollow rectangular guide is one connected conductor at one potential. By the uniqueness theorem, the only solution of Laplace’s equation with that boundary value is constant VV, which would give Et=0\mathbf E_t=0. A nontrivial TEM mode therefore needs at least two separate conductors at different instantaneous potentials, as in a two-wire or coaxial line.

FeatureTwo-wire lineCoaxial lineHollow waveguide
Conductorstwo exposed conductorsinner and outer conductorsone connected wall
Fundamental modeTEMTEMTE or TM
Low-frequency limitcan operate to DCcan operate to DChas a nonzero cutoff
Shieldingpoorexcellentexcellent
Dispersionideally nondispersiveideally nondispersivedispersive
Typical rangelow RFbroad RF rangemicrowave and high-power RF

For fields varying as e−jβze^{-j\beta z}, the longitudinal component ψ\psi, equal to HzH_z for TE modes or EzE_z for TM modes, satisfies the transverse Helmholtz equation

∂2ψ∂x2+∂2ψ∂y2+kc2ψ=0.\frac{\partial^2\psi}{\partial x^2} +\frac{\partial^2\psi}{\partial y^2} +k_c^2\psi=0.

Separation of variables and the perfect-conductor wall conditions quantize the transverse wavenumbers:

kx=mπa,ky=nπb,kc2=kx2+ky2.k_x=\frac{m\pi}{a}, \qquad k_y=\frac{n\pi}{b}, \qquad k_c^2=k_x^2+k_y^2.

The axial propagation constant is

β2=ω2με−kc2.\beta^2=\omega^2\mu\varepsilon-k_c^2.

At cutoff, β=0\beta=0. Substituting ωc=2πfc\omega_c=2\pi f_c therefore gives

fc,mn=12με(ma)2+(nb)2.f_{c,mn}=\frac{1}{2\sqrt{\mu\varepsilon}} \sqrt{\left(\frac{m}{a}\right)^2+\left(\frac{n}{b}\right)^2}.

For TE modes, mm and nn may individually be zero but not both. For TM modes, both indices must be nonzero. Above cutoff β\beta is real and the mode propagates; below cutoff it is imaginary and the mode is evanescent.

fc,10=12aμε.f_{c,10}=\frac{1}{2a\sqrt{\mu\varepsilon}}.

Rectangular waveguide mode patterns.

Rectangular waveguide mode patterns.

For operation above cutoff,

λg=λ1−(fc/f)2,\lambda_g=\frac{\lambda}{\sqrt{1-(f_c/f)^2}}, vp=v1−(fc/f)2,vg=v1−(fc/f)2.v_p=\frac{v}{\sqrt{1-(f_c/f)^2}}, \qquad v_g=v\sqrt{1-(f_c/f)^2}.

For TE and TM modes,

ZTE=η1−(fc/f)2,ZTM=η1−(fc/f)2.Z_{\text{TE}}=\frac{\eta}{\sqrt{1-(f_c/f)^2}}, \qquad Z_{\text{TM}}=\eta\sqrt{1-(f_c/f)^2}.

Waveguide dispersion above cutoff.

Waveguide dispersion above cutoff.

Key quantities are cutoff frequency, dominant mode, guide wavelength, phase velocity, group velocity and wave impedance.

Circular waveguide mode cues.

Circular waveguide mode cues.

At low frequency, inductors and capacitors can be treated as separate lumped elements. At microwave frequency, their dimensions may become comparable with wavelength, conductor loss increases, and stray reactances become important. A metallic cavity instead uses distributed electric and magnetic fields:

  • electric-field energy acts like energy stored in a capacitor;

  • magnetic-field energy acts like energy stored in an inductor;

  • wall and dielectric losses act like resistance;

  • only discrete field patterns and resonant frequencies satisfy all boundary conditions.

Consider a uniform waveguide carrying a TE or TM mode. Closing it with perfect electric conductor (PEC) plates at z=0z=0 and z=dz=d causes complete reflection. The forward and reflected waves combine to form a standing wave.

At a PEC wall,

n^×E=0,n^⋅B=0.\hat{\mathbf n}\times\mathbf E=0, \qquad \hat{\mathbf n}\cdot\mathbf B=0.

Thus the tangential electric field must vanish on every cavity wall. Surface charge supports a normal electric field, while surface current supports a tangential magnetic field.

For the end plates to coincide with standing-wave electric-field nodes, the axial phase condition is

βzd=pπ,p=1,2,3,…\beta_zd=p\pi, \qquad p=1,2,3,\ldots

or

d=pλg2,\boxed{d=\frac{p\lambda_g}{2}},

where

λg=2πβz\lambda_g=\frac{2\pi}{\beta_z}

is the guide wavelength of that mode. The cavity length must contain an integer number of guide half-wavelengths, not generally free-space half-wavelengths.

Shorted waveguide as a cavity.

Shorted waveguide as a cavity.

How to read the figure. The left-hand guide supports separate forward and reflected travelling waves. Adding PEC end plates forces repeated reflection and fixes electric-field nodes at the ends. On the right, the two waves have combined into a standing field. Only frequencies satisfying d=pλg/2d=p\lambda_g/2 reproduce the same phase after a round trip and build to a large amplitude.

There is no net time-average power flow through a lossless closed cavity. Energy remains stored and moves back and forth between electric and magnetic forms.

Take a homogeneous rectangular cavity with dimensions

0<x<a,0<y<b,0<z<d,0<x<a, \qquad 0<y<b, \qquad 0<z<d,

filled with a medium of permeability μ\mu and permittivity ε\varepsilon. Define

v=1με,k=ωμε.v=\frac{1}{\sqrt{\mu\varepsilon}}, \qquad k=\omega\sqrt{\mu\varepsilon}.

For the corresponding rectangular waveguide,

kc2=(mπa)2+(nπb)2k_c^2= \left(\frac{m\pi}{a}\right)^2 +\left(\frac{n\pi}{b}\right)^2

and

βz2=k2−kc2.\beta_z^2=k^2-k_c^2.

The end plates require

βz=pπd.\beta_z=\frac{p\pi}{d}.

Substitution gives the cavity eigenvalue equation

k2=(mπa)2+(nπb)2+(pπd)2.k^2= \left(\frac{m\pi}{a}\right)^2 +\left(\frac{n\pi}{b}\right)^2 +\left(\frac{p\pi}{d}\right)^2.

Therefore the resonant angular frequency is

ωmnp=πμε(ma)2+(nb)2+(pd)2,\omega_{mnp}= \frac{\pi}{\sqrt{\mu\varepsilon}} \sqrt{ \left(\frac{m}{a}\right)^2 +\left(\frac{n}{b}\right)^2 +\left(\frac{p}{d}\right)^2 },

and the resonant frequency is

fmnp=12με(ma)2+(nb)2+(pd)2.\boxed{ f_{mnp}= \frac{1}{2\sqrt{\mu\varepsilon}} \sqrt{ \left(\frac{m}{a}\right)^2 +\left(\frac{n}{b}\right)^2 +\left(\frac{p}{d}\right)^2 } }.

For an air-filled cavity,

fmnp=c2(ma)2+(nb)2+(pd)2.f_{mnp}= \frac{c}{2} \sqrt{ \left(\frac{m}{a}\right)^2 +\left(\frac{n}{b}\right)^2 +\left(\frac{p}{d}\right)^2 }.
ModeLongitudinal fieldAllowed indices
TEmnp\mathrm{TE}_{mnp}Ez=0E_z=0, Hz≠0H_z\ne0m,n=0,1,2,…m,n=0,1,2,\ldots, but not both zero; p=1,2,…p=1,2,\ldots
TMmnp\mathrm{TM}_{mnp}Hz=0H_z=0, Ez≠0E_z\ne0m,n=1,2,…m,n=1,2,\ldots; p=0,1,2,…p=0,1,2,\ldots

There is no non-zero TE00p\mathrm{TE}_{00p} field, and TM\mathrm{TM} modes cannot have m=0m=0 or n=0n=0. Unlike an ordinary propagating-wave condition, p=0p=0 is allowed for TM modes because EzE_z is normal to the end plates and need not vanish there.

Representative longitudinal field functions are

Hz=H0cos⁡(mπxa)cos⁡(nπyb)sin⁡(pπzd)H_z=H_0 \cos\left(\frac{m\pi x}{a}\right) \cos\left(\frac{n\pi y}{b}\right) \sin\left(\frac{p\pi z}{d}\right)

for TE modes, and

Ez=E0sin⁡(mπxa)sin⁡(nπyb)cos⁡(pπzd)E_z=E_0 \sin\left(\frac{m\pi x}{a}\right) \sin\left(\frac{n\pi y}{b}\right) \cos\left(\frac{p\pi z}{d}\right)

for TM modes. The remaining components follow from Maxwell’s curl equations.

Important examples are

f101TE=v21a2+1d2f_{101}^{\mathrm{TE}} =\frac{v}{2} \sqrt{\frac{1}{a^2}+\frac{1}{d^2}}

and

f110TM=v21a2+1b2.f_{110}^{\mathrm{TM}} =\frac{v}{2} \sqrt{\frac{1}{a^2}+\frac{1}{b^2}}.

Cavity mode cues.

Cavity mode cues.

How to read the figure. The left panel is a qualitative xx-zz cut of TE101\mathrm{TE}_{101}. The field changes once across xx and once along zz, and opposite signs indicate a 180∘180^\circ phase reversal across a node. The right panel shows TM110\mathrm{TM}_{110} in an xx-yy cut. The dots represent EzE_z normal to the page and to the end plates; it varies across both aa and bb but has no axial variation because p=0p=0.

The cycle-average energies are

We=14∭Vε∣E∣2 dVW_e=\frac{1}{4}\iiint_V \varepsilon|\mathbf E|^2\,dV

and

Wm=14∭Vμ∣H∣2 dV.W_m=\frac{1}{4}\iiint_V \mu|\mathbf H|^2\,dV.

At resonance in a lossless cavity,

We=Wm,\boxed{W_e=W_m},

and the total cycle-average stored energy is

W=We+Wm.W=W_e+W_m.

The equality refers to cycle-average energies. Instantaneously, electric and magnetic energy exchange every quarter-cycle:

  1. At an electric-field maximum, energy is mainly electric and the magnetic field is momentarily minimum.

  2. One quarter-cycle later, energy is mainly magnetic.

  3. Another quarter-cycle later, the electric field is maximum with reversed polarity.

  4. The process repeats, analogous to energy exchange between CC and LL in an ideal resonator.

Near a single isolated mode, a cavity can be represented by an equivalent RLC resonator with

ω0=1LC.\omega_0=\frac{1}{\sqrt{LC}}.

The equivalent circuit is a local model near resonance; the distributed cavity can support many separate modes, each with its own equivalent resonant branch.

An ideal PEC cavity would store energy forever and have infinite quality factor. A real cavity loses energy through several mechanisms.

Finite wall conductivity causes surface-current heating.

At high frequency,

Rs=ωμc2σ=1σδs,R_s=\sqrt{\frac{\omega\mu_c}{2\sigma}} =\frac{1}{\sigma\delta_s},

where

δs=2ωμcσ\delta_s=\sqrt{\frac{2}{\omega\mu_c\sigma}}

is skin depth. For peak-value phasors, conductor power loss is

Pc=Rs2∬S∣Ht∣2 dS.P_c=\frac{R_s}{2} \iint_S|\mathbf H_t|^2\,dS.

Conductor loss is strongest where tangential magnetic field, and therefore wall surface current, is large.

For a dielectric with loss tangent tan⁡δ\tan\delta, the time-average loss is

Pd=ωε′tan⁡δ2∭V∣E∣2 dV.P_d=\frac{\omega\varepsilon'\tan\delta}{2} \iiint_V|\mathbf E|^2\,dV.

For a uniformly filled low-loss cavity,

Qd≈1tan⁡δ.Q_d\approx\frac{1}{\tan\delta}.

Energy also leaves through coupling probes, loops, apertures, imperfect joints and leakage. External coupling is intentional when power must enter or leave the cavity, but it lowers the measured or loaded quality factor.

Q=ω0WPloss.\boxed{ Q=\omega_0\frac{W}{P_{\mathrm{loss}}} }.

Equivalently,

Q=2πenergy storedenergy lost per cycle.Q=2\pi \frac{\mathrm{energy\ stored}} {\mathrm{energy\ lost\ per\ cycle}}.

A high-QQ cavity has low loss, slow field decay, a sharp resonance and narrow bandwidth.

Unloaded, external and loaded quality factors

Section titled “Unloaded, external and loaded quality factors”
SymbolMeaning
QcQ_climitation from conducting-wall loss
QdQ_dlimitation from dielectric loss
Q0Q_0unloaded QQ due to all internal losses
QeQ_eexternal QQ due to energy extracted by coupling
QLQ_Lloaded QQ including internal and external losses

Internal loss mechanisms combine as

1Q0=1Qc+1Qd+1Qother.\frac{1}{Q_0}=\frac{1}{Q_c}+\frac{1}{Q_d}+\frac{1}{Q_{\mathrm{other}}}.

For one external coupling port,

1QL=1Q0+1Qe.\boxed{ \frac{1}{Q_L}=\frac{1}{Q_0}+\frac{1}{Q_e} }. βc=Q0Qe,\beta_c=\frac{Q_0}{Q_e},

so

QL=Q01+βc.Q_L=\frac{Q_0}{1+\beta_c}.
CouplingConditionInterpretation
Undercoupledβc<1\beta_c<1internal loss exceeds extracted power
Critically coupledβc=1\beta_c=1internal and external losses are equal
Overcoupledβc>1\beta_c>1external loading dominates

At critical coupling, Qe=Q0Q_e=Q_0 and QL=Q0/2Q_L=Q_0/2.

If the source is removed, stored energy decays approximately as

W(t)=W(0)e−ω0t/QL,W(t)=W(0)e^{-\omega_0t/Q_L},

while field amplitude decays as

∣E(t)∣∝e−ω0t/(2QL).|E(t)|\mathrel{\propto} e^{-\omega_0t/(2Q_L)}.

For a lightly damped single resonance, the normalized power response near f0f_0 is approximately

P(f)Pmax⁡≈11+4QL2(f−f0f0)2.\frac{P(f)}{P_{\max}} \approx \frac{1}{1+ 4Q_L^2\left(\dfrac{f-f_0}{f_0}\right)^2}.

At these points,

P(f1)=P(f2)=Pmax⁡2,P(f_1)=P(f_2)=\frac{P_{\max}}{2},

which is −3.01-3.01 dB relative to the peak. The half-power bandwidth is

Δf=f2−f1.\Delta f=f_2-f_1.

For QL≫1Q_L\gg1,

QL=f0Δf.\boxed{ Q_L=\frac{f_0}{\Delta f} }.

Thus a larger QLQ_L produces a narrower resonance curve.

Resonance curve and bandwidth.

Resonance curve and bandwidth.

How to read the figure. The horizontal axis is frequency normalized to the resonant frequency, so the peak occurs at f/f0=1f/f_0=1. The cyan dashed line is half the peak power, or −3-3 dB. Its two intersections with the response define f1f_1 and f2f_2. The illustrated curve has QL=100Q_L=100, so Δf/f0=1/100=0.01\Delta f/f_0=1/100=0.01 and the half-power points lie approximately at 0.995f00.995f_0 and 1.005f01.005f_0.

A cavity mode is excited efficiently only when the source has the correct field type, orientation and position. Placing a coupler at a field node gives little coupling even when the frequency is correct.

  • Place it near an electric-field maximum.

  • Align it parallel to the desired electric-field component.

  • Probe length and insertion depth control coupling strength.

  • Place it near a magnetic-field maximum.

  • Orient its plane so the desired magnetic field passes through the loop.

  • Loop area and rotation control coupling strength.

  • Position the aperture where the required waveguide and cavity fields overlap strongly.

  • Aperture size and shape control coupling.

  • Small apertures weakly perturb the cavity; a large iris increases loading and can shift the resonant frequency.

Cavity coupling methods.

Cavity coupling methods.

How to read the figure. The left sketch places an electric probe at an EE-field maximum and aligns it with the field. The centre sketch places a loop where HH is large so magnetic flux links the loop. The right sketch uses an iris in a shared waveguide wall; the travelling guide mode transfers power through the opening to the matching cavity mode.

Selective excitation is possible because orthogonal cavity modes have different field symmetries. A centrally placed probe may excite one mode strongly while giving zero coupling to another mode whose electric field has a node there.

Resonant frequency changes when cavity dimensions or material properties change:

f0∝1με.f_0\mathrel{\propto}\frac{1}{\sqrt{\mu\varepsilon}}.

Common tuning methods are

  • moving a conducting wall or plunger to change effective cavity dimensions;

  • inserting a metallic tuning screw where electric field is strong;

  • inserting dielectric material to increase effective permittivity and generally lower frequency;

  • changing temperature, which changes dimensions, conductivity and material properties.

A tuner also perturbs the field and can alter QQ, coupling and nearby-mode separation.

PropertyUniform waveguideResonant cavity
Structureopen or terminated transmission pathclosed conducting enclosure
Frequency conditionany f>fcf>f_c can propagateonly discrete fmnpf_{mnp} resonate strongly
Axial fieldtravelling wave is possiblestanding wave
Average power flowcarries power along the guideideally zero through the closed cavity
Main usetransfer microwave powerstore energy and select frequency

Resonant cavities are used in

  • microwave oscillators such as klystrons and magnetrons;

  • narrowband filters, duplexers and frequency-selective networks;

  • wavemeters and frequency standards;

  • radar and satellite communication equipment;

  • particle accelerators, where resonant electric fields accelerate charged particles;

  • electron-spin and nuclear-magnetic-resonance systems;

  • measurement of dielectric constant, loss tangent and surface resistance;

  • microwave heating and industrial processing.

For an air-filled rectangular waveguide with broad dimension a=4 cm=0.04 ma=4\ \mathrm{cm}=0.04\ \mathrm m, the dominant-mode cutoff is

fc,10=c2a=3.00×1082(0.04)=3.75 GHz.f_{c,10}=\frac{c}{2a} =\frac{3.00\times10^8}{2(0.04)} =\boxed{3.75\ \mathrm{GHz}}.

Below this frequency the TE10\mathrm{TE}_{10} field is evanescent. Practical single-mode operation must be above this cutoff and below the cutoff of the next mode.

An air-filled cavity has

a=4 cm,b=2 cm,d=5 cm.a=4\ \mathrm{cm}, \qquad b=2\ \mathrm{cm}, \qquad d=5\ \mathrm{cm}.

Find the TE101\mathrm{TE}_{101} resonant frequency.

For m=1m=1, n=0n=0 and p=1p=1,

f101=c21a2+1d2.f_{101}=\frac{c}{2} \sqrt{\frac{1}{a^2}+\frac{1}{d^2}}.

Substituting SI values,

f101=3×10821(0.04)2+1(0.05)2.f_{101}=\frac{3\times10^8}{2} \sqrt{ \frac{1}{(0.04)^2} +\frac{1}{(0.05)^2} }.

Therefore,

f101≈4.80 GHz.\boxed{f_{101}\approx4.80\ \mathrm{GHz}}.

The dimension bb does not appear because n=0n=0 for this TE mode.

A cavity resonates at f0=10f_0=10 GHz and has QL=2000Q_L=2000. Its half-power bandwidth is

Δf=f0QL=10×1092000=5×106 Hz.\Delta f=\frac{f_0}{Q_L} =\frac{10\times10^9}{2000} =5\times10^6\ \mathrm{Hz}.

Hence

Δf=5 MHz.\boxed{\Delta f=5\ \mathrm{MHz}}.

For a symmetric high-QQ response, the half-power frequencies are approximately

f1=9.9975 GHz,f2=10.0025 GHz.f_1=9.9975\ \mathrm{GHz}, \qquad f_2=10.0025\ \mathrm{GHz}.

Loaded quality factor under critical coupling

Section titled “Loaded quality factor under critical coupling”

If an unloaded cavity has Q0=6000Q_0=6000 and is critically coupled, then

Qe=Q0=6000Q_e=Q_0=6000

and

QL=Q01+βc=60002=3000.Q_L=\frac{Q_0}{1+\beta_c} =\frac{6000}{2} =3000.
  1. A cavity is a waveguide or conducting enclosure closed in all directions.

  2. PEC walls require zero tangential electric field and create standing waves.

  3. A rectangular cavity resonates at

fmnp=12με(ma)2+(nb)2+(pd)2.f_{mnp}=\frac{1}{2\sqrt{\mu\varepsilon}} \sqrt{ \left(\frac{m}{a}\right)^2 +\left(\frac{n}{b}\right)^2 +\left(\frac{p}{d}\right)^2 }.
  1. TE modes have Ez=0E_z=0; TM modes have Hz=0H_z=0.

  2. Electric and magnetic energies exchange every quarter-cycle and have equal cycle averages at resonance.

  3. Quality factor is Q=ω0W/PlossQ=\omega_0W/P_{\mathrm{loss}}.

  4. Loaded half-power bandwidth is Δf=f0/QL\Delta f=f_0/Q_L.

  5. Electric probes, magnetic loops and apertures couple to the corresponding field maxima.

  • Using free-space wavelength in d=pλg/2d=p\lambda_g/2 instead of guide wavelength.

  • Calling TE100\mathrm{TE}_{100} a valid closed-cavity mode; TE modes require p≥1p\ge1 when zz is the closed-guide axis.

  • Rejecting TM110\mathrm{TM}_{110} because p=0p=0; zero axial variation is allowed for TM modes.

  • Assuming En=0E_n=0 at a PEC wall. Only tangential EE must be zero; normal EE can be supported by surface charge.

  • Using unloaded Q0Q_0 in a measured bandwidth relation. The observed bandwidth gives loaded QLQ_L.